Home
Class 12
CHEMISTRY
CsCl has bc c arrangement and its unit c...

`CsCl` has `bc c` arrangement and its unit cell edge length is `400` pm. Calculate the interionic distance in `CsCl`.

Text Solution

Verified by Experts

The `bc c` arrangement of `CsCl` is shown in the figure below. The aim is to find half of the body diagonal `AE`. If the edge of the unit cell is `a`, then

`CE = sqrt(a^(2) + a^(2)) = sqrt2a`
`:. AE = sqrt((sqrt2a)^(2) + a^(2) = sqrt3a`
`= sqrt3 xx 400`
`:.` Interionic distance `= (1)/(2)AE`
`= sqrt3 xx 200 = 346.6`
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Solved Examples|13 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Exercises (Linked Comprehension)|13 Videos

  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise SUBJECTIVE TYPE|3 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Ex 2.3 (Objective)|9 Videos

Similar Questions

Explore conceptually related problems

CsCl has BCC structure and its unit cell edge length is 400 pm. Determine the interionic distance in CsCl.

An element A (Atomic weight =100 ) having b.c.c. structures has unit cell edge length 400 pm. Calculate the density of A. number of unit cells and number of atoms in 10 g of A.

A compound AB crystallises in the b.c.c lattice with unit cell edge length of 390 pm. Calculate (a) the distance between the oppsitely charged ions in the lattice. (b) the radius of A^(+) ion if radius of B^(-) ion is 175 pm.

An element 'x' (Atomic mass = 40 g mol^(-1) ) having f.c.c. structure has unit cell edge length of 400 pm. Calculate the density of 'x' and the number of unit cells in 4 g of 'x'

An element 'X' (At. Mass = 40 g mol^(-1) ) having f.c.c structure has unit cell edge length of 400 pm . Calculate the density of 'X' and the number of unit cells in 4 g of 'X' . (N_(A) = 6.022 xx 10^(23) mol^(-1)) .

If the unit cell edge length of NaCl crystal is 600 pm, then the density will be

CsBr has bcc structure with edge length of 43 pm . The shortest interionic distance between cation and anion is

CsBr has bcc stucture with edge length 4.3 pm .The shortest interionic distance in between Cs and Br is