Potassium chloride crystallize with a body-centred cubic lattice. Calculate the distance between the `200, 110,` and `222` Planes. The length of the side of the unit cell is `5.34 Å`.

Explanation

`d_(hkl) = (a)/(sqrt((h^(2) + k^(2) + l^(2)))`
For `200` plane `d_(200) = (a)/(sqrt((2^(2) + 0^(2) + 0^(2)))`
`= (5.34)/(sqrt4) = 2.67 Å`
For `110` plane, `d_(110) = (a)/((sqrt(1^(2) + 1^(2) + 0^(2)))`
`= (5.34)/(sqrt2) = 3.77 Å`
For `222` plane, `d_(222) = (a)/(sqrt((2^(2) + 2^(2) + 2^(2))))`
`= (5.34)/(sqrt2) = 1.54 Å`