If the radius of anion is `0.20 nm`, the maximum radius of cation which can be filleed in respective voids is correctly matched in

Options

A. `r_(o+) = 0.0828 nm` for tetrahedral void
B. `r_(o+) = 0.045 nm` for triangular void
C. `r_(o+) = 0.1464 nm` for tetrahedral void
D. None of the above.

Answer

A, B, C

Explanation

`r_(o+) // r_(ɵ) = 0.732, 0414`, and `0.225` maximum for `OV, TV`. and angular triangular defect.