An fcc lattice has a lattice parameter `a = 400` pm. Calculater the molar volume of the lattice including all the empty space.

Options

A. `10.8 mL`
B. `96 mL`
C. `8.6 mL`
D. `9.6 mL`

Answer

D

Explanation

Number of atoms `= N_(A)`
`rArr` Number of unit cells `= (N_(A))/(4)`
[`:' 4` atoms in each unit cell]
Volume of `1` mol lattice `= (N_(A))/(4) xx` Volume of unit cell
`= (6.023 xx 10^(23))/(4) xx (400 xx 10^(-12))^(3)m^(3) = 9.64 mL`