Henry law constant for oxygen dissolved in water is` 4.34 xx 10^(4) atm` at `25^(@) C`. If the partial pressure of oxygen in air is 0.4 atm.Calculate the concentration ( in moles per litre) of the dissolved oxygen in equilbrium with air at `25^@C`.

Explanation

To solve the problem, we will use Henry's Law, which states that the concentration of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. The formula for Henry's Law can be expressed as:

\[ C = \frac{P}{K_H} \]

Where:
- \( C \) is the concentration of the gas in the liquid (in moles per liter).
- \( P \) is the partial pressure of the gas (in atm).
- \( K_H \) is the Henry's Law constant (in atm).
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