Henry's law constant for oxygen and nitrogen dissolved in water at 298 K are `2.0 xx 10^(9)` Pa and` 5.0 xx 10^(9)` Pa , respectively . A sample of water at a temperature just above 273 K was equilibrated with air (20% oxygen and 80% nitrogen ) at 1 atm. The dissolved gas was separated from a sample of this water and the dried. Determine the composition of this gas.

Explanation

To determine the composition of the gas dissolved in water after equilibrating with air, we can follow these steps:

### Step 1: Understand the Given Data
- **Henry's Law Constants:**
- For Oxygen (O2), \( k_H = 2.0 \times 10^9 \, \text{Pa} \)
- For Nitrogen (N2), \( k_H = 5.0 \times 10^9 \, \text{Pa} \)
- **Composition of Air:**
- Oxygen (O2): 20%
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