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The vapour pressure of pure benzene at ...

The vapour pressure of pure benzene at `88^(@)C` is `957 mm` and that of toluene at the same temperature is `379.5 mm`. The composition of benzene-toluene misture boiling at `88^(@)C` will be

A

`chi_("benzene")=0.66 , chi_("toluene") = 0.34`

B

`chi_("benzene")=0.34, chi_("toluene") = 0.66`

C

`chi_("benzene")= chi_("toluene") = 0.5`

D

`chi_("benzene")=0.75, chi_("toluene") = 0.25`

Text Solution

Verified by Experts

The correct Answer is:
a
`p = p_("benzene").^(@)chi_("benzene")+ p_("toluence").^(@)chi_("toluence")`
760= 957
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