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Assuming ideal behaviour, calculate the ...

Assuming ideal behaviour, calculate the pressure of `1.0 molal` solution of a non-volatile molecular solute in water at `50@C` . The vapour presure of water at `50@C` is `0.222 atm`.

Text Solution

Verified by Experts

`P_("solution") = P_(A) = P_(A)@chi_(A)` (Raoult's law)
By using the relation between molarlity and mole fraction,
we have,
`m=chi_(B)/chi_(A) xx 1000/(Mw_(A)) = 1-chi_(A)/chi_(A) xx 1000/(Mw_(A))`
`rArr chi_(A) = 1000/(mMw_(A) + 1000)`
=`1000/(1 xx 18 + 1000) =1000/1018 = 0.982`
`rArr P_(solution) = P_(A)@chi_(A) = 0.222 xx 0.982 = 0.218 atm`
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