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The vapour pressure of methyl alcohol a...

The vapour pressure of methyl alcohol at `298 K` is 0.158 bar. The vapour pressure of this liquid in solution with liquid `B` is 0.095 bar. Calculate the mole fraction of methyl alcohol in the solution if the mixture obeys Raoult's law.

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Given `P@_("methyl alcohol") = 0.158` bar ltbargt `P_("solution") = 0.095` bar ltbargt According to Raoult's law
`P = chi_(1)P@` (`chi_(1)` = mole fraction of methyl alcohol)
`:. 0.095 = chi_(1) xx 0.158`
`chi_(1)` (mole fraction of methyl alcohol `= (0.095)/(0.158) = 0.601`
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