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The vapour pressure of acetone at 298 K ...

The vapour pressure of acetone at `298 K` is `40 mm` of `Hg`. Its mole fraction in a solution with alcohol is `0.80`. What is its vapour pressure in solution if the mixture obey Raoult's law?

Text Solution

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The given values are:
`P@_("acetone") = 40 mm` of `Hg`
`chi_("acetone") = 0.80`
According to Raoult's law
`P_(A) = P_(A)@chi_(A)`
On substituting all values, we get
Vapour pressure of acetone in solution `= 40 xx 0.80`
= 32 mm of Hg
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