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At 20^@C, the vapour pressure of pure li...

At `20^@C`, the vapour pressure of pure liquid `A` is `22 mm Hg` and that of pure liquid `B` is `75 mm Hg`. What is the composition of the solution of these two components that has vapour pressure of `48.5 mm Hg` at this temperature?

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To find the composition of the solution of two components A and B that has a vapor pressure of 48.5 mm Hg at 20°C, we can use Raoult's Law. Here’s a step-by-step solution: ### Step 1: Identify the given data - Vapor pressure of pure liquid A (Pₐ₀) = 22 mm Hg - Vapor pressure of pure liquid B (Pᵦ₀) = 75 mm Hg - Total vapor pressure of the solution (P_total) = 48.5 mm Hg ### Step 2: Define the mole fractions ...
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