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Lowering of vapour pressure due to a sol...

Lowering of vapour pressure due to a solute in `1` molal aqueous solution at `100^(@)C` is
a.`13.44 mm Hg` ,b. `14.14 mm Hg` ,c.`13.2 mm Hg` ,d. `35.2 mm Hg`

Text Solution

Verified by Experts

a. `Mw_(B) = (chi_(B)xx1000)/((1 - chi_(B))Mw_(A))`
`{:[(chi_(B)= "mole fraction of solute"),(Mw_(A)="molar mass of solvent")]:}`
`1= (chi_(B)xx1000)/((1 - chi_(B))xx18)`
`chi_(B) = 0.0176`
`chi_(A) = 1 - 0.0176 = 0.9824`
`P=P^(@)chi_(A) = 760 xx 0.9824 = 746.62`
`DeltaP = P^(@) -P = 760 - 746.62 ~~13.41`
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