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Calculate the vapour pressure of an aque...

Calculate the vapour pressure of an aqueous solution which contains `5 mass per per cent` of `urea`. The vapour pressure of pure water is `23.5 mm Hg`. The molar mass of `urea` is `60`.

Text Solution

Verified by Experts

Mass of urea = `5 g`
Mass of water =` (100 - 5) = 95 g`
Number of moles of urea = `5/60 = 0.083`
Number of moles of water =`95/18 =5.278`
Total number of moles = `5.278 + 0.083`
`=5.301`
Mole fraction of solvent = `5.278 / 5.361`
`P_(S)` = Mole fraction of sovent `xx P^(@)`
`5.278 /5.361 xx 23.5 = 3.14 mm Hg`
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