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The boiling point of a solution made by ...

The boiling point of a solution made by dissolving `12.0 g` of glucose in `100 g` of water is `100.34^(@)C`. Calculate the molecular weight of glucose, `K_(b)` for water `= 0.52^(@)C//m`.

Text Solution

Verified by Experts

Using the relation for the molecular weight of a solute from elevation in boiling point, we have
`Mw_(b) = K_(b)(W_(B)/(W_(A)DeltaT_(b)) xx 1000)`
`= 0.52 (12/(100 xx 0.34) xx 1000)`
`(DeltaT_(b) = 100.34 - 100 = 0.34^(@)C)`
`rArr Mw_(B) = 183.5 g mol^(-1)`
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