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By dissolving 13.6 g of a substance in 2...

By dissolving `13.6 g` of a substance in `20 g` of water, the freezing point decreased by `3.7^(@)C`. Calculate the molecular mass of the substance. (Molal depression constant for water `= 1.863K kg mol^(-1))`

Text Solution

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`Mw_(2)=(1000 K _(f)W_(2))/(W_(1)xxDeltaT)`
Given,`K_(f)=1.863 K kg mol^(-1)`
`W_(2)=13.6 g`,`W_(1)=20 g , DeltaT=3.7^(@)C`
`(Mw_(2)) = (1000xx1.863xx13.6)/(20xx3.7) =342.39`
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