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1.355 g of a substance dissolved in 55 g...

`1.355 g` of a substance dissolved in `55 g`of `CH_(3)COOH` produced a depression in the freezing point of `0.618^(@)C`. Calculate the molecular weight of the substance `(K_(f)=3.85)`

Text Solution

Verified by Experts

`DeltaT = (K)_(f)(W_(B)xx1000)/(Mw_(B)xxW_(A))`
where`W_(B)`= mass of solute ,`Mw_(B)`= molar mass of solute,
`W_(A)`= mass of solvent
`0.618 = 3.85 xx (1.355xx1000)/(Mw_(B)xx55)`
`Mw_(B)=153.47`
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