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The freezing point of 0.08 molal NaHSO(4...

The freezing point of `0.08 molal NaHSO_(4)` is `-0.345^(@)C`. Calculate the percentage of `HSO_(4)+O` ions that transfers a proton to water. Assume `100%` ionization of `NaHSO_(4)` and `K_(t)` for `H_(2)O = 1.86 K molality^(-1)`.

Text Solution

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`:.` Total particles after dissolution of `NaHSO_(4)`
`=1+1-h+h+h=2+h`
Now, `DeltaT_(f)=K_(f)xx` molality `xx(2+h)`
`:.2+h=2.319`
`:.h=0.319`
i.e.,`31.9%` of `HSO_(4)ө` shows proton transfer to `H_(2)O`.
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