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If a solution containing 6 g of tripheny...

If a solution containing `6 g` of triphenyl methane, `(C_(6)H_(5))_(3)CH ("molecular weight" =244)`,in `1000 g` of benzene is cooled to `0.22^(@)C`.below the freezing point of benzene, how much solvent will crystallize out and what will be the molality of residual solution? `(K_(f)=5.1 K m^(-1))`

Text Solution

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If the weight of benzene remaining as a liquid be `W_(1) g ` and assuming triphenyl methane to be soluble in liquid benzene,`DeltaT_(f)=K_(f)xxm DeltaT_(f)=0.22, K_(f)=5.1 K M^(-1)`
`0.22 = 5.1 xx m`
`m=0.0431372 = 0.043`
`m=(W_(2)xx1000)/(Mw_(2)xxW_(1))`
`(0.043)=(6xx1000)/(244xxW_(1)) rArr W_(1) =571.86 g`
Amount of benzene crystallizing out
`=1000-571.16 =428.14 g`
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