A solution obtained by mixing 100 mL of `20%` solution of urea (molar mass =60) and 100 mL of `1.6%` solution of cane sugar (molar mass =342) at `300 K`. (R=0.083 L bar `K^(-1) mol^(-1)`). Calculate
a.Osmotic pressure of urea solution
b.Osmotic pressure of cane sugar solution
c.Total osmotic pressure of solution

Explanation

The given values are
`W_("urea")=2.0 g`,`V=200 mL` , T=293 K
`W_("cane sugar")=1.2 g`,`Mw_("urea")=60` ,`Mw_("cane sugar")=342`
R=0.083 L bar `K^(-1) mol^(-1)`
Now using Van't Hoff equation,
`pi=CRT` or `(W_(2)RT)/(Mw_(2)V)`
a.Osmotic pressure of urea
`pi=(2.0xx0.083xx300)/(60xx0.2)=4.15` bar
b. Osmotic pressure of cane sugar
`pi=(2.0xx0.083xx300)/(342xx0.2)=0.43` bar
c.The total osmotic pressure of solution will be the sum of the somotic pressure produced by urea and cane sugar, respectively.
`:.pi_("total")=pi_("urea")+pi_("cane sugar")`
`=4.15+0.43=4.58` bar