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The osmotic pressure of a solution was f...

The osmotic pressure of a solution was found to be `8 atm` when `8 mol ` of a non-volatile solute was dissolved in `V` L of solution at `300 K`.Calculate the volume of solution `(R=0.0821 L-"atm" K^(-1) "mol"^(-1))`

Text Solution

Verified by Experts

The given values are
`pi=8 atm`,`T=300K`,`n_(B)=8`
`R=0.0821 L-"atm mol"^(-1)`
Now,using formula
`V=(nRT)/(pi)=(8xx0.0821xx300)/8 =246.3 L`
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