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A solution of an organic compound is pre...

A solution of an organic compound is prepared by dissolving `30 g` in `100 g` water. Calculate the molecular mass of compound and the osmotic pressure of solution at `300 K`, when the elevation in boiling point is `0.52` and `K_(b)` for water is `0.52 K m^(-1)`.

Text Solution

Verified by Experts

The given values are
`W_(B)=30 g`,`W_(A)=100 g`,`T=300 K `
`DeltaT_(b)=0.52 K m^(-1)`
Now, using formula
`Mw_(B)=(K_(f)xx1000xxW_(B))/(W_(A)xxDeltaT_(b))`
`=(0.52xx1000xx30)/(100xx0.52)=300 g`
For osmotic pressure,
`pi=(piRT)/V= W_(B)/Mw_(B)xx(RxxT)/V=30/300xx(0.082xx300)/(100//1000)`
=2.45 atm
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