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An M/10 solution of potassium ferrocyani...

An M/10 solution of potassium ferrocyanide is `46%` dissociated at `300 K`. What will be its osmotic pressure?

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Normal osmotic pressure`=W/(MwxxV)xxRxxT`
When no dissociation has taken place
`W/(Mw)=0.1`, `V=1 L`, `R=0.821`, `T=300 K`
Normal osmotic pressure =`0.1/1xx0.0821xx300`
`=2.463` atm

Potassium ferrocyanide is an electrolyte. It dissociates as
`{:(K_(4)[Fe(CN)_(6)],hArr,4K^(+),+,[Fe(CN)_(6)]^(4-),),(1-alpha,,4alpha,," "alpha.,"Total "=1+4alpha):}`

`i=1+4alpha=1+4xx0.46 = 2.84`

`"Observed osmotic pressure"/"Normal osmotic pressure" = 2.84/1`
Observed osmotic pressure = `2.84xx2.463=6.995` atm
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