Home
Class 12
CHEMISTRY
A certain substance A tetramerizes in wa...

A certain substance `A` tetramerizes in water to the extent of `80%`. A solution of `2.5 g` of `A` in `100 g` of water lowers the freezing point by `0.3^(@)C`. The molar mass of `A` is
a.`120` , b.`61` ,c.`60` ,d.`62`

Text Solution

AI Generated Solution

To find the molar mass of substance A, we can follow these steps: ### Step 1: Understand the tetramerization of substance A Substance A tetramerizes in water to the extent of 80%. This means that 80% of A forms a tetramer (A4), while 20% remains as monomers (A). ### Step 2: Determine the van 't Hoff factor (i) The van 't Hoff factor (i) can be calculated using the formula: \[ i = 1 - (1 - \frac{1}{n}) \cdot \alpha \] ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

When 250 mg of eugenol is added to 100 g of camphor (K_(f) = 39.7K "molality"^(-1)) , it lowered the freezing point by 0.62^(@)C . The molar mass of eugenol is:

A solution made by dissolving 0.32 of a new compound in 25g of water has freezing point -0.201^(@)C .the molecular mass of the new compound.

A certain mass of substance in 10 g of benzene lowers the freezing point by 1.28^(@)C and in 100 g of water lowers the freezing point by 1.395^(@)C separately. If the substance has normal molecular weight in benzene and completely dissociated in water, calculate number of moles of ions formed by its 1 mole dissociation in water (K_(f_("water"))=1.86, K_(f_("benzene"))=5.00)

When 250 mg of eugenol is added to 100 g of camphor (k_(f)=39.7" molality"^(-1)) , it lowered the freezing point by 0.62^(@)C . The molar of eugenol is :

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 K kg mol ^(-1))