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A 0.025 m solution of monobasic acids ha...

A `0.025 m` solution of monobasic acids has a freezing point of `-0.060^(@)C`. What are `K_(a)` and `pK_(a)` of the acid? `(K_(f)=1.86^(@)C)`

Text Solution

Verified by Experts

`DeltaT_(f)=iK_(f)m` , `0.60 =ixx1.86xx0.25`
`:.i=1.29`

`:.i=1-alpha+alpha=1+alpha`
`:.alpha=0.29`
`K_(a)=(Calpha)^(2)/(1-alpha)=(0.025xx(0.29^(2)))/(1-0.29) =3xx10^(-3) rArr pK_(a)=2.5`
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