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A mixture of 0.1 mol of Na(2)O and 0.1 ...

A mixture of `0.1 mol ` of `Na_(2)O` and `0.1 mol ` of `BaO` is dissolved in `1000 g` of `H_(2)O`. Calculate the vapour pressure of solution at `373 K`.

Text Solution

Verified by Experts

`Na_(2)O` and `BaO` both are ionic compounds and are completely ionized to give `3` and `2 ions`, respectively,
`(i) Na_(2)O rarr 2Na^(o+) O^(2)-(i=3)`
`(ii)BaO rarr Ba^(2+) + O^(2-) (i=2)`
`:.(P^(@)-P_(s))/P^(@) = ichi_(Na_(2)O) + ichi_(BaO)`
`(760-P_(s))/(760) =3xx(0.1)/(0.1+0.1+55.5)+2xx (0.1)/(0.1+0.1+55.5)`
`:.P_(s)=753.21 mm Hg`
Alternatively
Total number of ions=`5xx0.1=0.5`
`(P^(@)-P_(s))/P^(s) =n_(2)/n_(1) =0.5/55.5 =0.009`
`760-P_(s)/P_(s)=0.009`
Solve for `P_(s) rArr 753.21 mm Hg`.
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