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For a 0.01 M CH(2)COOH solution, wedge(m...

For a `0.01 M CH_(2)COOH` solution, `wedge_(m)=7.8 Omega^(-1)cm^(2) mol^(-1)` if `wedge_(m)^(@)=390Omega^(-1)cm^(2)mol^(-1)` . What is the degree of the dissociation `(alpha)` of acetic acid ?

A

`0.20`

B

`0.48`

C

`0.02`

D

`0.05`

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha=(wedge^(c)._(m))/(wedge^(@)._(m))`=(7.8)/(390)=0.02`
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