In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log `(x/m)` axis was found to be `0.3010` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `0.5` atm` .

Explanation

According to the Freundlich equation
`(x)/(m)=KP^(1//n)`
or log `(x)/(m)=logK+(1)/(n)log P`
`:.` plot of log `(x)/(m)` versus log `p` is linear with slope `=(1)/(n)` and intercept = log K
Thus, `(1)/(n)=tantheta=tan45^(@)=1` or `n=1` .
log `K=0.3010` or K=antilog `0.3010=2`
At `P=0.5atm`
`(x)/(m)=KP^(1//n)=2xx(0.5)^(1)=1.0`