Time required to decompose `SO_(2)Cl_(2)` to half of its intial amount is `60 mi n.` If the decomposition is a first order reaction, calculate the rate constant of the reaction.

Answer

`1.925xx10^(-4)s^(-1)`

Explanation

`t_(1//2)=60 mi n`
For first order reaction,
`k=(0.693)/(t_(1//2))=(0693)/(60 mi n)`
`=1.155xx10^(-2)mi n^(-1)`
`=(1.55xx10^(-2))/(60s)=1.925xx10^(-4)s^(-1)`