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0.002 gm of an organic compound was trea...

0.002 gm of an organic compound was treated according to Kjeldahl's method. `0.2xx10^-4` mol of `H_2SO_4` was required to neutralise `NH_3`. Calculate the percentage of `N_2`

Text Solution

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m. mole of `H_2SO_4=0.2xx10^-4xx10^3=0.2xx10^-1`
mEq. Of `H_4SO_4=0.2xx10^-1xx2=0.4xx10^-1=0.04`
Percentage of `N_2`
`=(1.4xx"mEq. Of acid used to neutralise "NH_3)/("weight of compound")`
`=(1.4xx0.04)/(0.002)=28%`
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