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0.16 gm of a dibasic organic acid requir...

0.16 gm of a dibasic organic acid required 25.0 ml of `(N)/(10)NaOH` for complete neutralisation. Calculate its molucular mass.

Text Solution

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mEq. Of `NaOH=25xx(1)/(10)=2.5`
mEq. Of acis `=2.5`
equivalent of acid `=2.5xx10^-3`
`Ew=("weight")/("equivelent acid")=(0.16)/(2.5xx10^-3)=64gm`
molecular mass of acid `=64xx2=128`
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