0.45 gm of an organic compound gave on combution 0.792 gm of `CO_2` and `0.324gm` of water. 0.24 gm of the same substance was Kjeldahlised and the ammonia liberated was absorbed in 50.0 ml of `(M)/(8H_2SO_4)`. The excess acid required 77.0 ml of `(N)/(10)NaOH` for complete neutralisation. Calculate the empirical formula of the compound.

Explanation

To find the empirical formula of the organic compound, we will follow these steps:

### Step 1: Calculate the moles of Carbon (C) from CO₂
1. **Find the molar mass of CO₂**:
- Molar mass of CO₂ = 12 (C) + 16*2 (O) = 44 g/mol
2. **Calculate moles of CO₂ produced**:
- Moles of CO₂ = mass of CO₂ / molar mass of CO₂ = 0.792 g / 44 g/mol = 0.018 moles
3. **Calculate moles of Carbon (C)**:
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