0.76 gm of the silver salt of a diabasic acid was ignited. It gave 0.54 gm of pure siver. Determine the molecular mass of the acid.

Explanation

Mass of the silver salt taken `=076gm`
mass of the silver left `=0.54gm`
Basicity of the acid `=2`
To calculate the equivalent mass of acid (E)
Applying the relation
`("weight of silver salt")/("Equivel ent weight of silver salt")`
`=("weight of the silver")/("Equivelent weight of silver")`, we get `(0.76)/(E+107)=(0.54)/(108)`
Thus, the equivalent weight of acid `(E)=45`. The acid of dibasec.
`Mw=Ewxx`basicity
`=45xx2`
`=90`
Thus the molecular mass of the dibasic acid is 90.