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10 mL of a mixture of CH(4),C(2)H(4) and...

10 mL of a mixture of `CH_(4),C_(2)H_(4) and CO_(2)` was exploded with excess oxygen. After explosion, there ws a contraction of 17 mL on cooling and there was a further contraction of 14 mL on treatment with KOH. Find out the composition of the mixture.

Text Solution

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Let the volume of `CH_4=xml`
Volume of `(CH_2=CH_2)=yml`
Volume of `CO_2=[10-(x+y)]ml`
(i) `CH_4(g)+2O_2(g)rarrCO_2(g)+2H_2O(l)`
(ii) `CH_2=CH_2(g)+3O_2(g)rarr2CO_2(g)+H_2O(l)`
Volume of `CO_2` absorbed by `KOH=14ml`
Volume of `CO_2=x+2y+[10-(x+y)]=14`
`y=4ml`
volume of gaseous reactant`=`Volume of gaseous products `+` contraction
`x+2x+y+3y=x+2y+17`
`3x+4y-x-2y=17`
`2x+2y=17`
`2x+2xx4=17`
`2x=9`
`x=4.5ml`
Volume of `CH_4=4.5ml`
volume of `(CH_2=CH_2)=4ml`
volume of `CO_2=10-(4.5+4)`
`=1.5ml`
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