0.38 gm of a silver salt of a dibasic acid on ignition gave 0.27 gm of silver. Calculate the molecular mass of the acid.

Explanation

Mass of silver salt `=0.38gm`
Mass of silver `=0.27gm`
`("equivalent mass of silversalt")/("equialent mass of silver")=("mass of silver salt")/("mass of siver")`
Equivalent mass of silver salt `=(0.38)/(0.27)xx108`
`E_107=(0.38)/(027)xx108` (`E=` Equivalent mass of acid)
`E=[(0.38)/(0.27)xx108-107]=45`
Molecular mass of the acid `=` equivalet mass `xx` basicity `=45xx2=90`