projectile is fired from ground at an angle `theta` with horizontal. The elevation angle `phi` of heighest point as seen from launch point is related by the relation-

Options

A. `tanphi=2tantheta`
B. `tanphi=tan theta`
C. `tanphi=(tantheta)/(2)`
D. `tanphi=(tan theta)/(4)`

Answer

C

Explanation

`tan phi=(H)/(R//2)=(u^(2)sin^(2)theta//2g)/(u^(2)sin2theta//2g)=(tan theta)/(2)`