A particle executing simple harmonic motion with an amplitude A and angularr frequency `omega`. The ratio of maximum acceleration to the maximum velocity of the particle is

Options

A. `omegaA`
B. `omega^(2)A`
C. `omega`
D. `(omega^(2))/(A)`

Answer

C

Explanation

In SHM,
Maximum velocity, `v_(max)=omegaA`
Maximum acceleration, `a_(max)=omega^(2)A`
`therefore(a_(max))/(v_(max))=(omega^(2)A)/(omegaA)=omega`