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A particle travels in a circle of radius...

A particle travels in a circle of radius 20 cm at a speed thast uniformly increases. If the speed changes from 5.0 m/s to 6.0 m/s in 2.0s, find the angular aceleration.

Text Solution

Verified by Experts

Since speed increases uniformly, average tangrntial acceleration is equal to instaneous tangential acceleration.
Therefore, the instantaneous tangential acceleration is given by
`a_t = (d v)/(d t)= (v_2 - v_1)/(t_2 - t_1)`
=`(6.0 - 5.0)/(2.0) ms^-1 = 0.5 m s^-2`
The angular acceleration is `prop = a_t //r`
=`(0.5 ms^-2)/(20 cm) = 2.5 rad s^-2`.
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