Home
Class 11
PHYSICS
A time varying force F=6t-2t^(2)N, at t=...

A time varying force `F=6t-2t^(2)N`, at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at `t=0` the force `F=0`. Now answer the following:
Find the time when the velocity attained by the body is maximum.

A

2s

B

3s

C

3.5s

D

4.5s

Text Solution

Verified by Experts

The correct Answer is:
B
If we draw F-t graph, we can see that upto `t=3s, force is positive, so velocity increase up to 3s and after that velocity starts decreasing. So at 3s, velocity is maximum.
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS|Exercise Integer|5 Videos

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS|Exercise Assertion-reasoning|15 Videos

  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|10 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS|Exercise Integer type|1 Videos

Similar Questions

Explore conceptually related problems

A time varying force F=6t-2t^(2)N , at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at t=0 the force F=0 . Now answer the following: Mark the correct statement:

A time varying force F=6t-2t^(2)N , at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at t=0 the force F=0 . Now answer the following: Find the duration for which the force acts on the body.

If S=6t^(2)-t^(3) , then the body comes to rest after time t=

A body starts from rest at time t = 0 , the acceleration time graph is shown in the figure . The maximum velocity attained by the body will be

A force given by the relation F = 8t, acts on a body of mass 2 kg, initially at rest. Find the work done by this force on the body during first 2 seconds of its motion

The displacement of a body of mass 2 kg veries with time t as S = t^(2) + 2t , where S is in seconds. The work done by all the forces acting on the body during the time interval t = 2s to t = 4s is

A force given by the relation F = 8t, (F in Newton and t in sec.) acts on a body of mass 2kg. Initially at rest. Choose the correct option.

A variable force acts on a body of mass m (initially at rest) from t = 0 to t = t_(0) . The curve of F plotted versus t is semicircle as shown, then -

CENGAGE PHYSICS-NEWTON'S LAWS OF MOTION 1-Linked Comperhension
  1. In the arrangement shown in fig., all pulleys are smooth and massless....

    Text Solution

    |

  2. In the arrangement shown in fig., all pulleys are smooth and massless....

    Text Solution

    |

  3. In the arrangement shown in fig., all pulleys are smooth and massless....

    Text Solution

    |

  4. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  5. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  6. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  7. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  8. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  9. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  10. Two containers of sand are arranged like the block as shown in fig. th...

    Text Solution

    |

  11. Two containers of sand are arranged like the block as shown in fig. th...

    Text Solution

    |

  12. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

    Text Solution

    |

  13. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

    Text Solution

    |

  14. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

    Text Solution

    |

  15. For the system shown in fig, there is no friction anywhere. Masses m(1...

    Text Solution

    |

  16. For the system shown in fig, there is no friction anywhere. Masses m(1...

    Text Solution

    |

  17. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  18. A mass M is suspended as shown in fig. The system is in equilibrium. A...

    Text Solution

    |

  19. A mass M is suspended as shown in fig. The system is in equilibrium. A...

    Text Solution

    |

  20. A mass M is suspended as shown in fig. The system is in equilibrium. A...

    Text Solution

    |