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A mass M is suspended as shown in fig. T...

A mass M is suspended as shown in fig. The system is in equilibrium. Assume pulleys to be massless. K is the force constant of the spring.

The extension produced in the spring is given by

A

`4Mg//K`

B

`Mg//K`

C

`2Mg//K`

D

`3Mg//K`

Text Solution

Verified by Experts

The correct Answer is:
A
`T=Mg`
`T_(1)=T+Mg = 2Mg`
`Kx = 2T_(1)`
or `x=(2T_(1))/(K) = (4Mg)/(K)`
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