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A mass M is suspended as shown in fig. T...

A mass M is suspended as shown in fig. The system is in equilibrium. Assume pulleys to be massless. K is the force constant of the spring.

Find the net tension force acting on the lower support.

A

`Mg`

B

`2Mg`

C

`3Mg`

D

`4Mg`

Text Solution

Verified by Experts

The correct Answer is:
C

Total tension on lower support:
`T_(1)+T=2 Mg +Mg= 3Mg`.
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CENGAGE PHYSICS-NEWTON'S LAWS OF MOTION 1-Linked Comperhension
  1. In the arrangement shown in fig., all pulleys are smooth and massless....

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  2. In the arrangement shown in fig., all pulleys are smooth and massless....

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  3. In the arrangement shown in fig., all pulleys are smooth and massless....

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  8. Two smooth block are placed at a smooth corner as shown in fig. Both t...

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  9. Two smooth block are placed at a smooth corner as shown in fig. Both t...

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  13. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

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  14. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

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  15. For the system shown in fig, there is no friction anywhere. Masses m(1...

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  16. For the system shown in fig, there is no friction anywhere. Masses m(1...

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  17. Two blocks of masses m(1) and m(2) are connected with a light spring o...

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  18. A mass M is suspended as shown in fig. The system is in equilibrium. A...

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  19. A mass M is suspended as shown in fig. The system is in equilibrium. A...

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