There is minimum magnitude of force required both in horizontal and verticle direction either to side ao lift up the block will first slide or lift up will depend apon which miximum magnitude of force is lesser

For verticle to start litting up
`F sin 37^(@) + N ge Mg`
`N` becomes zero just lifting condition
`F ge (Mg)/(sin 37^(@))`
`F_("lift") ge (10g)/(3//5) or F_("lift") ge (500)/(3) N`
For horizontal direction to starrt sliding
`F cos 37^(@) ge mu_(s)N`
`F cos 37^(@) gt 0.5[10g - F sin 37^(@)]`
`( :' N = 10g - F sin 37^(@))`
Hence `F _("slide") gt (50)/(cos 37^(@) + 0.5 sin 37^(@))`
` F _("slide") gt (500)/(11)N`
`F_("lift") gt (500)/(3) rArr F_("slide") lt F_("lift")`