A block of mass M is kept on as rough horizontal surface. The coefficient of static friction between the block and the surface is `mu`. The block is to be pulled by applying a force to it. What minimum force is needed to slide the block? In which direction should this force act?
Text Solution
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The correct Answer is:
60
a The block can be moved with least effort on a rough surface `(mu)` if the force is applied at the angle of friction `(lambda)` Then is `lambda = theta = tan^(-1) mu_(s)` That block should be pullied at the angle of friction i,e, `theta = tan^(-1) (0.75) = 37^(@)` b. The magnitude of external force is `F_(min) = mg sin theta ` `= (10)(10) sin 37^(@) = (100) ((3)/(5)) = 60N `
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CENGAGE PHYSICS-NEWTON'S LAWS OF MOTION 2-Integer type
