A block lying on an inclined plane has a weigh of `50 N` .It just beings to side down when inclination of plane with the horizontal is `30^(@)` find the coefficient of static plane friction .
Text Solution
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The block reaches the point of sliding when the the plane makes an angle of `30^(@)` with the horizontal .Hence , `30^(@)` is the angle of repose , so `mu _(s) = tan 30^(@) = 1//sqrt(3)`
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CENGAGE PHYSICS-NEWTON'S LAWS OF MOTION 2-Integer type
