The motion of the motor car over a convex bridge `AB` is the motion along the segment of a circle `AB` (Fig ) .The centripetal force is proveded by the difference of weight `mg` of the car and the normal reaction `R` of the bridge

`:. mg - R = (mv^(2))/(r )`
or `R = mg - (mv^(2))/(r )`
Clearly `R lt mg` i,e the weight of moving car is less than the weight of the statinary car