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Block B rests on a smooth surface .The c...

Block B rests on a smooth surface .The coefficient of static friction between A and B is `mu = 0.4` where `F = 30 N` then
Acceleration of lower block is

A

`3//7 ms^(-2)`

B

`4//3 ms^(-2)`

C

`6//7 ms^(-2)`

D

`3//2 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
c
For upper block
`a_(max)= mg = 4ms^(-2)` and `f_(max) = 40 N`
a. when `F = 30N`,as `F ltf_(max)`
so both blocks will move togather
`:. A = (F)/(M +m) = (30)/(15)= (6)/(7)ms^(-2)`
b. when `F = 250 N`
For upper block: `250 - 40 = 10a_(1)`
`210 = 10a_(1) rArr a_(1) = 21ms^(-2)`
For block
`a_(2) = (40)/(25)= (8)/(5)ms^(-2)`
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Knowledge Check

  • Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

    A
    `3//2 ms^(-2)`
    B
    `6//7 ms^(-2)`
    C
    `4//3 ms^(-2)`
    D
    `3//7 ms^(-2)`

  • The coefficient of static friction between the two blocks is 0.363. What is the acceleration of block 1 so that block 2 does not fall ?

    A
    `6 ms^(-2)`
    B
    `12 ms^(-2)`
    C
    `18 ms^(-2)`
    D
    `27 ms^(-2)`

  • In the figure shown, a block of weight 10 N resting on a horizontal surface. The coefficent of static friction between the block and the surface mu_(s)=0.4 . A force of 3.5 N will keep the block in uniform motion, once it has been set in motion. A horizontal force force of 3N is applid to the block, then the block will

    A
    Move over the surface with constant velocity
    B
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    C
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    D
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