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A block of mass m is on an inclined plan...

A block of mass m is on an inclined plane of angle `theta`. The coefficient of friction between the block and the plane is `mu` and `tanthetagtmu`. The block is held stationary by applying a force P parallel to the plane. The direction of force pointing up the plane is taken to be positive. As P is varied from `P_1=mg(sintheta-mucostheta)` to `P_2=mg(sintheta+mucostheta)`, the frictional force f versus P graph will look like

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
a
Initially the friction force is upward as `P lt mg sin theta` .As `P` increases frictional force decreases and at value of `P= mg sin theta` friction will be zero Afterward friction will the direction and start increasing
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