The phase difference between two points is `pi//3`. If the frequency of wave is 50 Hz, then what is the distance between two points?
`("Given, "v=330 ms^(-1))`

Options

A. 2.2 m
B. 1.1 m
C. 0.6 m
D. 1.7 m

Answer

B

Explanation

Phase difference `= (2pi)/(lamda) xx` path difference. From relation, `Delta phi = (2pi)/(lamda) xx Delta x rArr Delta x = (lamda)/(2pi) xx Delta phi`..(i)
Also, `lamda = (v)/(n)`…..(ii)
Now, from Eqs. (i) and (ii), we get
`Deltax = (v)/(2pi n) xx Delta phi = (330)/(2pi xx 50) xx (pi)/(3) = 1.1 m`