If temperature of black body increases from `300K` to `900K`, then the rate of energy radiation increases by

Options

A. 81
B. 3
C. 9
D. 2

Answer

A

Explanation

We can write , `((T_(2))/T_(1))^(4)=(E_(2))/(E_(1))`
`(E_(2))/(E_(1))=((900)/(300))^(4)rArr(E_(2))/(E_(1))=(3)^(4)` ,
`E_(2)=81E_(1)rArr(E_(2))/(E_(1))=81`