If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture is

Options

A. `1.40`
B. `1.50`
C. 1.53
D. 3.07

Answer

B

Explanation

`gamma_("mix")=((mu_(1)gamma_(1))/(gamma_(1)-1)+(mu_(2)gamma_(2))/(gamma_(2)-1))/((mu_(1))/(gamma_(1)-1)+(mu_(2))/(gamma_(2)-1))=((1xx(5)/(5))/([(5)/(3)-1])+(1xx(7)/(5))/([(7)/(5)-1]))/([(1)/((5)/(3)-1)]+[(1)/((7)/(5)-1)])=(3)/(2)=1.5`