A Carnot engine has the same efficiency between `800 K` to `500 K` and `x K to 600 K`. The value of `x` is

Options

A. 100 K
B. 960 K
C. 846 K
D. 754 K

Answer

B

Explanation

As, `eta=1-(T_(2))/(T_(1))=1-(500)/(800)=1-(600)/(x)`
`therefore(3)/(8)=1-(600)/(x)rArr(600)/(x)=1-(3)/(8)=(5)/(8)`
5x=4800
`x=(4800)/(5)=960 K`